蓝桥杯算法练习 - 报时助手


问题描述:

给定当前的时间,请用英文的读法将它读出来。

时间用时h和分m表示,在英文的读法中,读一个时间的方法是:

如果m为0,则将时读出来,然后加上“o’clock”,如3:00读作“three o’clock”。
如果m不为0,则将时读出来,然后将分读出来,如5:30读作“five thirty”。

时和分的读法使用的是英文数字的读法,其中0~20读作:
0:zero, 1: one, 2:two, 3:three, 4:four, 5:five, 6:six, 7:seven, 8:eight, 9:nine, 10:ten, 11:eleven, 12:twelve, 13:thirteen, 14:fourteen, 15:fifteen, 16:sixteen, 17:seventeen, 18:eighteen, 19:nineteen, 20:twenty。
30读作thirty,40读作forty,50读作fifty。

按上面的规则21:54读作“twenty one fifty four”,9:07读作“nine seven”,0:15读作“zero fifteen”。

输入格式:

输入包含两个非负整数h和m,表示时间的时和分。非零的数字前没有前导0。h小于24,m小于60。

输出格式:

输出时间时刻的英文。

样例输入:

0 15

样例输出:

zero fifteen

实现:

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import java.util.Scanner;

public class Timer {

public static void main(String[] args){
System.out.println("Please input hour min:");
Scanner scanner = new Scanner(System.in);
int hour = 0;
int min = 0;
while(scanner.hasNext()){
hour = scanner.nextInt();
min = scanner.nextInt();

String[] time1 = {
"zero","one","two","three","four","five","six","seven",
"eight","nine", "ten", "eleven", "twelve", "thirteen",
"fourteen", "fifteen", "sixteen", "seventeen",
"eighteen", "nineteen","twenty"
};
String[] time2 = {"twenty","thirty","forty","fifty"};

if(hour < 20){
System.out.print(time1[hour]);
if(min == 0){
System.out.print(" " + "o'clock");
}else if(min < 20){
System.out.print(" " + time1[min]);
}else{
System.out.print(" " + time2[min/10 - 2] + " " + time1[min%10]);
}
}else{
System.out.print(time2[0] + " " + time1[hour-20]);
if(min == 0){
System.out.print("o'clock");
}else if(min < 20){
System.out.print(" " + time1[min]);
}else{
System.out.print(" " + time2[min/10 - 2] + " " + time1[min%10]);
}
}
}
}
}

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